输入
第一行是n(n <=30)，表示有n组数据
接下来n行，每行是一组数据。
每行三个整数y,m,d，分别代表年，月，日。(-1000000<=y<=1000000)
若今年是2017年，则往前就是2016年，2015年....一直数到2年，1年，再往前就是0年，-1年，-2年.....
输出
对每组数据，输出星期几，星期几分别用
"Sunday","Monday","Tuesday","Wednesday","Thursday", "Friday","Saturday" 表示
如果月份和日期不合法，输出"Illegal"
样例输入
62017 2 292017 13 20 1 1-2 3 42017 10 182015 12 31
样例输出
IllegalIllegalSaturdayWednesdayWednesdayThursday
n=int(input())week={0:"Wednesday",1:"Thursday", 2:"Friday",3:"Saturday", 4:"Sunday",5:"Monday",6:"Tuesday"}month={1:31,2:28,3:31,4:30,5:31,6:30,7:31,8:31,9:30,10:31,11:30,12:31}oringal='2020 11 18'def ifmax(x): y=x.split() d,e,f=int(y[0]),int(y[1]),int(y[2]) if d>2020: return 1 elif d<2020: return 0 else: if e>11: return 1 elif e<11: return 0 else: if f>18: return 1 elif f<18: return 0 else: return -1t=''for i in range(n): day=0 month[2]=28 s=input() ss = s.split() a, b, c = int(ss[0]), int(ss[1]), int(ss[2]) if (b>=1 and b<=12)and(c>=1 and c<=month[b]): if ifmax(s)==-1: t=t+"Wednesday"+'n' elif ifmax(s)==1: if a % 4 == 0 and a % 100 != 0 or a % 400 == 0: month[2] = 29 for i in range(1, b): day += month[i] day += c day -=323 for j in range(2020,a): if j % 4 == 0 and j % 100 != 0 or j % 400 == 0: day += 366 else: day += 365 t += str(week[day % 7]) + 'n' else: if a % 4 == 0 and a % 100 != 0 or a % 400 == 0: month[2] = 29 for i in range(1,b): day+=month[i] day+=c day=323-day for j in range(a,2020): if j % 4 == 0 and j % 100 != 0 or j % 400 == 0: day += 366 else: day += 365 t += str(week[(-day) % 7]) + 'n' else: t += 'Illegaln'print(t)