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10进制转8进制怎么转?

时间:2023-06-03

hi各位大佬好,我是最帅的小明哥,今天依旧是搬砖的晚上,想到今天的题目还没搞定,因而记录下来,

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从网上搜索到一个简版,如下:(修改语言后)

def ten2eight(num): if num==0: return num else: j=num%8 i=num//8 ten2eight(i) print(j)print(ten2eight(32))print(ten2eight(100))

直接执行上述脚本可见正确答案,但比较Low,还有None出现

40None144None

1-去掉None

后来发现去不掉,因为执行时不满足条件相当于返回None,举例子如下:

>>> def func(num):..、 pass..、>>> print(func(8))None

所以下面仍旧有None打印出来

def ten2eight(num): if num: j=num%8 i=num//8 ten2eight(i) print(j)print(ten2eight(36))print(ten2eight(100))

留作坑。

2-class中函数不能用递归??

class Solution: def __init__(self): self.ans='' def ten2eight(self,num): if num: j=num%8 i=num//8 ten2eight(i)#这么做不对 self.ans+=str(j)sol=Solution()sol.ten2eight(32)print('result',sol.ans)$ python3 mycode.py 4result 0

更正后,可以正确执行了,如下:

class Solution: def __init__(self): self.ans='' def ten2eight(self,num): if num: j=num%8 i=num//8 self.ten2eight(i) self.ans+=str(j)sol=Solution()sol.ten2eight(302)print('result',sol.ans)$ python3 mycode.py result 456

3-class另一种形式

class Solution: def ten2eight(self,num): self.ans='' def func(num): if num: j=num%8 i=num//8 func(i) self.ans+=str(j) func(num) return self.anssol=Solution()res=sol.ten2eight(302)print("result2",res)result2 456

那么受上面启发,上面的坑可填??还是不行哦,还是class中的参数可以。

def ten2eight(num): ans='' def func(num): if num: j=num%8 i=num//8 func(i) ans+=str(j) func(num) return ansres2=ten2eight(698)print("results",res2)Traceback (most recent call last): File "mycode.py", line 103, in res2=ten2eight(698) File "mycode.py", line 101, in ten2eight func(num) File "mycode.py", line 99, in func func(i) File "mycode.py", line 99, in func func(i) File "mycode.py", line 99, in func func(i) File "mycode.py", line 100, in func ans+=str(j)UnboundLocalError: local variable 'ans' referenced before assignment

愿我们终有重逢之时,而你还记得我们曾经讨论的话题。

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