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LeetCode104:树的深度

时间:2023-06-05
题目: 代码:

# Definition for a binary tree node.# class TreeNode:# def __init__(self, val=0, left=None, right=None):# self.val = val# self.left = left# self.right = rightclass Solution: def maxDepth(self, root: Optional[TreeNode]) -> int: countleft = 0 countright = 0 def countDepth(root:TreeNode): if root == None: return 0 else: countleft = countDepth(root.left) countright = countDepth(root.right) if countleft >= countright: countleft += 1 return countleft else: countright += 1 return countright return countDepth(root)

结果:

 

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